Evaluate the following integrals:

∫ tan 2x tan 3x tan 5x dx

We know tan5x = tan(2x + 3x)


tan(A + B) =


tan(2x + 3x) =


tan(5x) =


tan(5x)(1 - tan2x.tan3x) = tan(2x) + tan(3x)


tan(5x) - tan2x.tan3x.tan5x = tan(2x) + tan(3x)


tan(5x) - tan(2x) - tan(3x) = tan2x.tan3x.tan5x


Substituting the above result in given equation we get





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