Evaluate the following integrals:
In this equation, we can manipulate numerator
Cos3x = cos2x.cosx
∴ Now the equation becomes,
⇒
Cos2x = 1 - sin2x
⇒
Now,
Let us assume sinx = t
d(sinx) = dt
cosx dx = dt
Substitute values of t and dt in the above equation
⇒
⇒
⇒
⇒
But t = sinx
⇒ .