Evaluate the following integrals:
In this equation, we can manipulate numerator
sin3x = sin2x.sinx
∴ Now the equation becomes,
⇒
sin2x = 1 - cos2x
⇒
Now ,
Let us assume cosx = t
d(cosx) = dt
- sinx dx = dt
Substitute values of t and dt in above equation
⇒
⇒
⇒
⇒
But t = cosx
⇒