Evaluate the following integrals:

Question

Philoid · Accepted Answer

Assume x² + 1 = t

⇒d(x² + 1) = dt

⇒2x dx = dt

⇒

x³ can be write as x².x

∴ Now the given equation becomes

⇒

x² + 1 = t ⇒ x² = t - 1

⇒

But t = (x² + 1)

⇒