Evaluate the following integrals:

Assume, 2x2 + 3x + 1 = t


d(x2 + x + 1) = dt


(4x + 3)dx = dt


Substituting t and dt in above equation we get


⇒


⇒


⇒


But t = 2x2 + 3x + 1


⇒ 2(2x2 + 3x + 1)1/2 + c.


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