Evaluate the following integrals:
∫ 2x sec3 (x2 + 3) tan (x2 + 3) dx
sec3 (x2 + 3) can be written as sec2 (x2 + 3). sec (x2 + 3)
Now the question becomes
⇒
Assume sec (x2 + 3) = t
d(sec (x2 + 3)) = dt
2x sec (x2 + 3) tan (x2 + 3)dx = dt
Substituting t and dt in the given equation
⇒
⇒
⇒ .