Evaluate the following integrals:
Assume sin - 1x = t
d( sin - 1x) = dt
⇒ 
∴ Substituting t and dt in given equation we get
⇒ 
⇒ 
But t = sin - 1x
⇒ 
.
57
Evaluate the following integrals:
Assume sin - 1x = t
d( sin - 1x) = dt
⇒
∴ Substituting t and dt in given equation we get
⇒
⇒
But t = sin - 1x
⇒ .