Evaluate the following integrals:
∫ sin3 x cos6 x dx
Since power of sin is odd, put cos x = t
Then dt = -sin xdx
Substitute these in above equation,
∫ sin3 x cos6 x dx = 
= 
= 
= 
= 
( since ∫xⁿ dx = 
+ c 
)
= 
5
Evaluate the following integrals:
∫ sin3 x cos6 x dx
Since power of sin is odd, put cos x = t
Then dt = -sin xdx
Substitute these in above equation,
∫ sin3 x cos6 x dx =
=
=
=
= ( since ∫xⁿ dx = + c )
=