Evaluate the following integrals:

∫ e2x sin (3x + 1) dx

Let I = ∫ e2x sin (3x + 1) dx


Now Integrating by parts choosing sin (3x + 1) as first function and e2x as second function we get,




Now again integrating by parts by taking cos(3x + 1) as first function and e2x as second function we get,





Therefore,






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