Evaluate the following integrals:
∫ e2x sin (3x + 1) dx
Let I = ∫ e2x sin (3x + 1) dx
Now Integrating by parts choosing sin (3x + 1) as first function and e2x as second function we get,
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Now again integrating by parts by taking cos(3x + 1) as first function and e2x as second function we get,
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Therefore,
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