Evaluate the following integrals:
∫ e2x sin (3x + 1) dx
Let I = ∫ e2x sin (3x + 1) dx
Now Integrating by parts choosing sin (3x + 1) as first function and e2x as second function we get,
Now again integrating by parts by taking cos(3x + 1) as first function and e2x as second function we get,
Therefore,