Evaluate the following integral:
Let
Now,
2x + 1 = A(x – 1) + B(x + 1)
Put x = 1
2 + 1 = A × 0 + B × 2
3 = 2B
Put x = – 1
– 2 + 1 = – 2A + B × 0
– 1 = – 2A
Therefore,