Evaluate the following integral:

Let



Now,


Let


2x + 1 = A(x – 1) + B(x + 1)


Put x = 1


2 + 1 = A × 0 + B × 2


3 = 2B



Put x = – 1


– 2 + 1 = – 2A + B × 0


– 1 = – 2A





Therefore,



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