Evaluate the following integral:

dx



X2 + 1 = A(x – 2)(x + 3) + B(x + 3) + C(x – 2)2


Put x = 2


4 + 1 = B × 5


5 = 5B



Put x = – 3


10 = C × 25



Equating coefficients of constants


1 = – 6A + 3B + 4C




Thus,




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