Evaluate the following integral:

dx



X2 + x – 1 = A(x + 1)(x + 2) + B(x + 2) + C(x + 1)2


Put x = – 2


1 = C



Put x = – 1


– 1 = B



Equating coefficients of constants


– 1 = 2A + 2B + C




Thus,





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