Evaluate the following integral:
1 = A(x + 1)(x2 + 1) + B(x2 + 1) + (Cx + D)(x + 1)2
= Ax3 + Ax2 + Ax + A + Bx2 + B + Cx3 + 2Cx2 + Cx + Dx2 + 2D + D
= (A + C)x3 + (A + B + 2C + D)x2 + (A + C + 2D)x + (A + B + D)
Equating constants
1 = A + B + D
Equating coefficients of x3
0 = A + C
Equating coefficients of x2
0 = A + B + 2C + D
Equating coefficients of x
0 = A + C + 2D
Solving we get
Thus,