Evaluate the following integral:



1 = A(x + 1)(x2 + 1) + B(x2 + 1) + (Cx + D)(x + 1)2


= Ax3 + Ax2 + Ax + A + Bx2 + B + Cx3 + 2Cx2 + Cx + Dx2 + 2D + D


= (A + C)x3 + (A + B + 2C + D)x2 + (A + C + 2D)x + (A + B + D)


Equating constants


1 = A + B + D


Equating coefficients of x3


0 = A + C


Equating coefficients of x2


0 = A + B + 2C + D


Equating coefficients of x


0 = A + C + 2D


Solving we get



Thus,




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