Evaluate the following integral:



3x + 5 = A(x – 1)(x + 1) + B(x + 1) + C(x – 1)2


Put x = 1


8 = 2B


B = 4


Put x = – 1


– 3 + 5 = 4C


2 = 4C



Put x = 0


5 = – A + B + C






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