For, x=0, 10 = 4B + 3D .... (i)

For, x=1, 14 = 5A + 5B + 4C + 4D .... (ii)

For, x= – 1,14 = – 5A + 5B – 4C + 4D .... (iii)

Also, by comparing coefficient of x³ we get, 0=A + C (iv)

On solving, (i), (ii), (iii), (iv) we get,

A=0, B= – 2, C=0, D=6