For, x=0, 19 = – 5B + 3D .... (i)

For, x=1, 26 = – 4A – 4B + 4C + 4D .... (ii)

For, x= – 1,14 = 4A – 4B – 4C + 4D .... (iii)

Also, by comparing coefficient of x³ we get, 0=A + C (iv)

On solving, (i), (ii), (iii), (iv) we get,