Given

This is a first order linear differential equation of the form

Here, P = cot x and Q = 2 sin x cos x

The integrating factor (I.F) of this differential equation is,

We have

∴ I.F = sin x [∵ e^{log x} = x]

Hence, the solution of the differential equation is,

Let sin x = t

⇒ cosxdx = dt [Differentiating both sides]

By substituting this in the above integral, we get

Recall

[∵ t = sin x]

Thus, the solution of the given differential equation is