Solve the following initial value problem:
Given differential equation
Find: Find the general solution of this differential equation.
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On Integrating we get,
= y – 2log|y + 2|=log |x| + log |C| ….(i)
Put y = 0, x = 2
= 0 – 2log2 = log 2 + log c
= -2 log 2 –log 2 = log C
= -3 log 2 = log c
= =log c
Put the value of C in equation (i)
Hence, y – 2log|y + 2|=