In a culture the bacteria count is 100000. The number is increased by 10% in 2 hours. In how many hours will the count reach 200000, if the rate of growth of bacteria is proportional to the number present.
Let y be the number of bacteria at any instant t
It is given that the rate of growth of the bacteria is proportional to the number present.
=
= (where k is a constant)
=
Integrating both sides, we get
=
= log y = kt + C
Let y0 be the number of bacteria at t = 0.
= log y0 = C
Substitute the value of C in, we get
⟹ log y = kt + log y0
= log y - log y0 = kt
=
Also, it is given that the number of bacteria increased by 10% in 2 hours.
=
=
Substituting the value,
=
= k =
Therefore,
=
=
Now, the time when the number of bacteria increases from 100000 to 200000 be t1.
= at t = t1
Now, =
Hence, in hours the number if bacteria increases from 100000 to 200000.