Consider the differential equation

=

=

=

Let 1-y² = t then -2y dy = dt Let log x = v

=

= .....(1)

Substitute the value of v and t in eq (2)

= …..(2)

Put x =1 and y =3 in eq (2)

=

= C =

Put the value of C in eq (2)

=

Hence, The particular solution is