Coloured balls are distributed in four boxes as shown in the following table:
A box is selected at random and then a ball is randomly drawn from the selected box. The colour of the ball is black, what is the probability that ball drawn is from the box III.
Given:
Box I has 3 Black, 4 White, 5 Red, 6 Blue balls
Box II has 2 Black, 2 White, 2 Red, 2 Blue balls
Box III has 1 Black, 2 White, 3 Red, 1 Blue balls
Box IV has 4 Black, 3 White, 1 Red, 5 Blue balls
Let us assume U1, U2, U3, U4 and A be the events as follows:
U1 = choosing Box I
U2 = choosing Box II
U3 = choosing Box III
U4 = choosing Box IV
A = choosing Black ball from box
We know that each urn is most likely to choose. So, probability of choosing a urn will be same for every Urn.
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The Probability of choosing balls from each box differs from box to box and the probabilities are as follows:
⇒ P(A|U1) = P(Choosing black ball from Box I)
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⇒ P(A|U2) = P(Choosing black ball from Box II)
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⇒ P(A|U3) = P(Choosing black ball from Box III)
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⇒ P(A|U3) = P(Choosing black ball from Box III)
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Now we find
P(U3|A) = P(The black ball is from BallIII)
Using Baye’s theorem:
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∴ The required probability is .