Given:

Bag contains 8 red and 6 green balls

It is told that three balls are drawn without replacement.

We need to find the probability that at least two balls drawn are green.

The possible cases of drawing balls are as shown below:

i. Green,Green,Red

ii. Green,Red,Green

iii. Red,Green,Green

iv. Green,Green,Green

⇒ P(D_at2greens) = P(GGR) + P(GRG) + P(RGG) + P(GGG)

Since drawing balls are independent events so, the probabilities multiply each other.

⇒

⇒

⇒

⇒

⇒

∴ The required probability is .