Arun and Tarun appeared for an interview for two vacancies. The probability of Arun’s selections is 1/4 and that of Tarun’s rejection is 2/3. Find the probability that at least one of them will be selected.
Given that,
⇒ P(AS) = P(Arun’s selection)
⇒
⇒ P(AN) = P(Arun’s rejection)
⇒
⇒
⇒ P(TN) = P(Tarun’s rejection)
⇒
⇒ P(TS) = P(Tarun’s selection)
⇒
⇒
We need to find the probability that at least one of them will be selected
⇒ P(Satone) = P(Selecting at least one of them)
⇒ P(Satone) = P(selecting only Arun) + P(selecting only Tarun) + P(Selecting both)
Since selection of each person is an independent event their probabilities multiply each other
⇒
⇒
⇒
⇒
∴ The required probability is .