A 60 g bullet fired from a 5 kg gun leaves with a speed of 500 m/s. Find the speed (velocity) with which the gun recoils (jerks backwards).
Mass of bullet, m1 = 0.06 kg,
Speed of bullet, v1 = 500m/s
Mass of gun, m2 = 5kg,
Velocity of recoil of gun, v2 = ?
By using the law of conservation of momentum,
0.06×500 = 5×v2
v2 = 0.06*500/5
= 6m/s
Hence, the gun recoils with the velocity of 6m/s.