An urn contains 7 red and 4 blue balls. Two balls are drawn at random with replacement. Find the probability of getting.
i. 2 red balls
ii. 2 blue balls
iii. One red and one blue ball
Given:
Urn contains 7 red and 4 blue balls
It is told that two balls are drawn with replacement
Let us find the probability of drawing each marble from bag
⇒ P(B) = P(Drawing a Blue Ball)
⇒
⇒
⇒
⇒ P(R) = P(Drawing a Red Ball)
⇒
⇒
⇒
We need to find the probability that the balls drawn:
i. Both in red colour
ii. Both in blue colour
iii. One red and one blue
⇒ P(SRR) = P(drawing Two red colour balls)
Since drawing a ball is an independent event, the probabilities multiply each other.
⇒
⇒
⇒
⇒ P(SBB) = P(drawing two blue colour balls)
Since drawing a ball is independent for each bag, the probabilities multiply each other.
⇒
⇒
⇒
⇒ P(Sany) = P(drawing Blue and red ball in any order)
⇒ P(Sany) = P(drawing Blue ball followed by red) + P(drawing Red ball followed by Blue)
Since drawing a ball is an independent event, the probabilities multiply each other.
⇒
⇒
⇒
⇒ .
∴ The required probabilities are .