A 1000 kg vehicle moving with a speed of 20 m/s is brought to rest in a distance of 50 metres:
(i) Find the acceleration.
(ii) Calculate the unbalanced force acting on the vehicles.
Vehicle Mass = 1000 kg
Initial Velocity (that is speed) let it be u = 20 ms-1
Final Velocity let it be v= 0ms-1
Distance travelled = 50 m
Let the acceleration be "a"
From equation = v2 = u2 + 2as
Putting all value
0= 20 + 2*a*50
0= 400+ 100a
0- 400= 100a (Side changing)
-400 = 100a
-400/ 100 = a (Side changing)
-4= a
a = -4 m/s2
This shows that the acceleration is in opposite direction that means it is retardation.
Retardation = 4m/s2