Given

For this inequation to be true, there are two possible cases.

i. 6x – 5 > 0 and 4x + 1 < 0

⇒ 6x – 5 + 5 > 0 + 5 and 4x + 1 – 1 < 0 – 1

⇒ 6x > 5 and 4x < –1

However,

Hence, this case is not possible.

ii. 6x – 5 < 0 and 4x + 1 > 0

⇒ 6x – 5 + 5 < 0 + 5 and 4x + 1 – 1 > 0 – 1

⇒ 6x < 5 and 4x > –1

However,

Thus, the solution of the given inequation is.