Given

For this inequation to be true, there are two possible cases.

i. 2x – 3 > 0 and 3x – 7 > 0

⇒ 2x – 3 + 3 > 0 + 3 and 3x – 7 + 7 > 0 + 7

⇒ 2x > 3 and 3x > 7

However,

Hence,

ii. 2x – 3 < 0 and 3x – 7 < 0

⇒ 2x – 3 + 3 < 0 + 3 and 3x – 7 + 7 < 0 + 7

⇒ 2x < 3 and 3x < 7

However,

Hence,

Thus, the solution of the given inequation is.