Given 3x – 6 > 0 and 2x – 5 > 0

Let us consider the first inequality.

3x – 6 > 0

⇒ 3x – 6 + 6 > 0 + 6

⇒ 3x > 6

⇒ x > 2

∴ x ∈ ( 2, ∞) (1)

Now, let us consider the second inequality.

2x – 5 > 0

⇒ 2x – 5 + 5 > 0 + 5

⇒ 2x > 5

(2)

From (1) and (2), we get

Thus, the solution of the given system of inequations is