Solve the following quadratic equations by factorization method:
x2 + (1 – 2i)x – 2i = 0
x2 + (1 – 2i)x – 2i = 0
Given x2 + (1 – 2i)x – 2i = 0
⇒ x2 + x – 2ix – 2i = 0
⇒ x(x + 1) – 2i(x + 1) = 0
⇒ (x + 1)(x – 2i) = 0
⇒ x + 1 = 0 or x – 2i = 0
∴ x = –1 or 2i
Thus, the roots of the given equation are –1 and 2i.