Given = 0

Recall that the roots of quadratic equation ax² + bx + c = 0, where a ≠ 0, are given by

Here, a = 1, and

By substituting i² = –1 in the above equation, we get

We can write

[∵ i² = –1]

[∵ (a – b)² = a² – 2ab + b²]

By using the result, we get

[∵ i² = –1]

Thus, the roots of the given equation are and.