Given

We need to find f(1), f(–1), f(0) and f(2).

When x > 0, f(x) = 4x + 1

Substituting x = 1 in the above equation, we get

f(1) = 4(1) + 1

⇒ f(1) = 4 + 1

∴ f(1) = 5

When x < 0, f(x) = 3x – 2

Substituting x = –1 in the above equation, we get

f(–1) = 3(–1) – 2

⇒ f(–1) = –3 – 2

∴ f(–1) = –5

When x = 0, f(x) = 1

∴ f(0) = 1

When x > 0, f(x) = 4x + 1

Substituting x = 2 in the above equation, we get

f(2) = 4(2) + 1

⇒ f(2) = 8 + 1

∴ f(2) = 9

Thus, f(1) = 5, f(–1) = –5, f(0) = 1 and f(2) = 9.