If, find:
i.
ii. f(–2)
iii. f(1)
iv.
v.
Given
i.
When 0 ≤ x ≤ 1, f(x) = x
ii. f(–2)
When x < 0, f(x) = x2
⇒ f(–2) = (–2)2
∴ f(–2) = 4
iii. f(1)
When x ≥ 1,
∴ f(1) = 1
iv.
We have
When x ≥ 1,
v.
We know is not a real number and the function f(x) is defined only when x ∈ R.
Thus, does not exist.