Given f(x) = x² and g(x) = 2x + 1

Both f(x) and g(x) are defined for all x ∈ R.

Hence, domain of f = domain of g = R

i. f + g

We know (f + g)(x) = f(x) + g(x)

⇒ (f + g)(x) = x² + 2x + 1

∴ (f + g)(x) = (x + 1)²

Clearly, (f + g)(x) is defined for all real numbers x.

∴ Domain of (f + g) is R

Thus, f + g : R → R is given by (f + g)(x) = (x + 1)²

ii. f – g

We know (f – g)(x) = f(x) – g(x)

⇒ (f – g)(x) = x² – (2x + 1)

∴ (f – g)(x) = x² – 2x – 1

Clearly, (f – g)(x) is defined for all real numbers x.

∴ Domain of (f – g) is R

Thus, f – g : R → R is given by (f – g)(x) = x² – 2x – 1

iii. fg

We know (fg)(x) = f(x)g(x)

⇒ (fg)(x) = x²(2x + 1)

∴ (fg)(x) = 2x³ + x²

Clearly, (fg)(x) is defined for all real numbers x.

∴ Domain of fg is R

Thus, fg : R → R is given by (fg)(x) = 2x³ + x²

iv.

We know

Clearly, is defined for all real values of x, except for the case when 2x + 1 = 0.

2x + 1 = 0

⇒ 2x = –1

When, will be undefined as the division result will be indeterminate.

Thus, the domain of = R –