If A and B are sets, then prove that A – B, A B and B – A are pair wise disjoint.

Let x ϵ A and y ϵ B


A – B = The set of values of A that are not in B.


A B = The set containing common values of A and B


B – A = The set of values of B that are not in A.


Two sets X and Y are called disjoint if,


X Y = ϕ


(A – B) (A B) = ((A – B) A) ((A – B) B)


(A – B) (A B) = ϕ ϕ


(A – B) (A B) = ϕ


Similarly,


(B – A) (A B) = ((B – A) A) ((B – A) B)


(B – A) (A B) = ϕ


Hence, the three sets are pair wise disjoint.


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