If A, B, C are three sets such that A ⊂ B, then prove that C – B ⊂ C – A.
We have, ACB.
To show: C – B ⊂ C – A
Let, x ϵ C–B
⇒ x ϵ C and x∉ B
⇒ x ϵ C and x∉ A
⇒ x ϵ C – A
Thus, x ϵ C–B ⇒ x ϵ C – A
This is true for all x ϵ C–B
∴ C – B ⊂ C – A