In a survey of 100 persons, it was found that 28 read magazine A, 30 read magazine B, 42 read magazine C, 8 read magazines A and B, 10 read magazines A and C, 5 read magazines B and C and 3 read all the three magazines. Find:
How many read magazine C only?
n(C) = 42 –(7+3+2)

= 42–12.

= 30.

Question

n(C) = 42 –(7+3+2)

= 42–12.

= 30.

Philoid · Accepted Answer

n(C) = 42 –(7+3+2)

= 42–12.

= 30.