How many different boat parties of 8, consisting of 5 boys and 3 girls, can be made from 25 boys and 10 girls?
Given we need to find the different boat parties of 8, consisting of 5 boys and 3 girls.
The selections of girls and boys are to be made from 25 boys and 10 girls.
Let us assume the number of ways of choosing to be N.
⇒ N = (no. of ways of choosing 5 boys) × (No. of ways of choosing 3 girls)
⇒ N = (25C5) × (10C3)
We know that ,
And also n! = (n)(n – 1)(n – 2)…………2.1
⇒
⇒
⇒
⇒ N = (53130) × (120)
⇒ N = 6375600
∴ The total no. of different boat parties are 6375600 ways.