Given that we need to find the no. of ways of obtaining a product by multiplying two or more from the numbers 3, 5, 7, 11.

The following are the cases the product can be done,

i. Multiplying two numbers

ii. Multiplying three numbers

iii. Multiplying four numbers

Let us assume the total numbers of ways of the product be N

⇒ N = (no. of ways of multiplying two numbers) + (no. of ways of multiplying three numbers) + (no. of multiplying four numbers)

⇒ N = ⁴C₂ + ⁴C₃ + ⁴C₄

We know that

And also n! = (n)(n – 1)(n – 2)…………2.1

⇒

⇒

⇒

⇒ N = 6 + 4 + 1

⇒ N = 11

∴ The total number of ways of product is 11 ways.