In an examination, a student to answer 4 questions out of 5 questions; questions 1 and 2 are however compulsory. Determine the number of ways in which the student can make a choice.

Given that student have to answer 4 questions from 5 questions.


It is also told that questions 1 and 2 are compulsory.


It is similar to answering the 2 questions out of the remaining 3 questions as 1 and 2 are compulsory.


Let us assume the no. of ways of answering the questions be N.


N = No. of ways of answering 2 questions from remaining 3 questions.


N = 3C2


We know that ,


And also n! = (n)(n – 1)......2.1





N = 3


The no. of answering the questions is 3.


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