Given that we need to find the no. of diagonals of

A hexagon

We know that the hexagon has 6 vertices and each side and diagonal can be formed by joining two vertices of a hexagon,

We know that hexagon has 6 sides,

Let us assume the no. of diagonals of the hexagon are N,

⇒ N = (no. of lines formed on joining any two vertices) – (no. of sides of the hexagon)

⇒ N = ⁶C₂ – 6

We know that ,

And also n! = (n)(n – 1)......2.1

⇒

⇒

⇒

⇒ N = 15 – 6

⇒ N = 9

∴ The total no. of diagonals formed is 9.