A bag contains 5 black and 6 red balls. Determine the number of ways in which 2 black and 3 red balls can be selected.

Given that we need to draw 2 black and 3 red balls from a bag of 5 black and 6 red balls.


Let us assume the no. of ways of drawing be N.


N = (no. of ways of selecting 2 black balls from 5 black balls) × (no. of ways of selecting 3 red balls from 6 red balls)


N = (5C2) × (6C3)


We know that ,


And also n! = (n)(n – 1)......2.1





N = 10 × 20


N = 200


The no. of ways of drawing 2 black and 3 red balls is 200.


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