A bag contains 5 black and 6 red balls. Determine the number of ways in which 2 black and 3 red balls can be selected.
Given that we need to draw 2 black and 3 red balls from a bag of 5 black and 6 red balls.
Let us assume the no. of ways of drawing be N.
⇒ N = (no. of ways of selecting 2 black balls from 5 black balls) × (no. of ways of selecting 3 red balls from 6 red balls)
⇒ N = (5C2) × (6C3)
We know that ,
And also n! = (n)(n – 1)......2.1
⇒
⇒
⇒
⇒ N = 10 × 20
⇒ N = 200
∴ The no. of ways of drawing 2 black and 3 red balls is 200.