If in a ∆ABC, A = 45o, B = 60o, and C = 75o; find the ratio of its sides.


Let a, b, c be the sides of the given triangle. Then by applying the sine rule, we get



Now substituting the given values we get





( sin (a + b) = sin a cos b + sin b cos a)


Now substituting the corresponding values, we get,





Multiplying 2√2, we get



Hence the ratio of the sides of the given triangle is


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