In ∆ABC, if a = 18, b = 24 and c = 30 and C = 90o, find sin A, sin B and sin C.


Let a, b, c be the sides of the given triangle. Then by applying the sine rule, we get




Now substituting the given values we get






Similarly,



Now substituting the given values we get






And given C = 90°, so sin C = sin 90° = 1.


Hence the values of sin A, sin B, sin C are respectively


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