In any triangle ABC, prove the following:
Let a, b, c be the sides of any triangle ABC. Then by applying the sine rule, we get
⇒a = k sin A
Similarly, b = k sin B
So, a - b = k(sin A - sin B)
And a + b = k(sin A + sin B)
So, the given LHS becomes,
But,
Substituting the above values in equation (i), we get
Rearranging the above equation we get,
Hence proved