In any triangle ABC, prove the following:

Let a, b, c be the sides of any triangle ABC. Then by applying the sine rule, we get
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⇒a = k sin A
Similarly, b = k sin B
So, a - b = k(sin A - sin B)
And a + b = k(sin A + sin B)
So, the given LHS becomes,
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But,
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Substituting the above values in equation (i), we get

Rearranging the above equation we get,



Hence proved