In any triangle ABC, prove the following:

Let a, b, c be the sides of any triangle ABC. Then by applying the sine rule, we get




a = k sin A


Similarly, b = k sin B


So, a - b = k(sin A - sin B)


And a + b = k(sin A + sin B)


So, the given LHS becomes,





But,




Substituting the above values in equation (i), we get



Rearranging the above equation we get,





Hence proved


4