In any triangle ABC, prove the following:

Let a, b, c be the sides of any triangle ABC. Then by applying the sine rule, we get
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⇒ a = k sin A, b = k sin B, c = k sin C
So the LHS of the given equation, we get
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Substituting values from sine law, we get
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Now consider the second part of the equation, we get
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Substituting values from sine law, we get
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Now consider the third part of the equation, we get
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Substituting values from sine law, we get
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From equation (i), (ii), and (iii), we get
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Hence proved