Compute
(ii)
(iii). L.C.M. (6!, 7!, 8!)
i. Given
= 30 × 29
= 870
ii. Given
We know that:
11! = 11 × 10 × 9 × … × 1
10! = 10 × 9 × 8 × … × 1
9! = 9 × 8 × 7 × … × 1
Putting these values, we get,
= 110 – 10
Hence,
iii. We have to find LCM of 6!, 7!, and 8!
We can write as,
= 8! = 8 × 7 × 6!
= 7! = 7 × 6!
= 6! = 6!
Therefore,
L.C.M (6!, 7!, 8!) = LCM [8 × 7 × 6!, 7 × 6!, 6! ]
= 8 × 7 × 6!
Hence, LCM is 8!