If (n + 2)! = 60 [(n – 1)!], find n.
Given (n + 2)! = 60 [(n – 1)!]
To Find : n
⇒ (n + 2) × (n + 1) × (n) × (n-1)! = 60 [(n – 1)!]
⇒(n + 2) × (n + 1) × (n) = 60
⇒ (n + 2) × (n + 1) × (n) = 5 × 4 × 3
n = 3
Hence, n = 3