If (n + 2)! = 60 [(n – 1)!], find n.

Given (n + 2)! = 60 [(n – 1)!]


To Find : n


(n + 2) × (n + 1) × (n) × (n-1)! = 60 [(n – 1)!]


(n + 2) × (n + 1) × (n) = 60


(n + 2) × (n + 1) × (n) = 5 × 4 × 3


n = 3


Hence, n = 3


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