Let P(n) be the statement: 2n ≥ 3n. If P(r) is true, show that P(r + 1) is true. Do you conclude that P(n) is true for all nϵN?
If P(r) is true then 2r ≥ 3r
For, P(r+1)
2r+1=2.2r
For, x>3, 2x>x+3
So, 2.2r>2r+3 for r>1
⇒ 2r+1>2r+3 for r>1
⇒ 2r+1>3r +3 for r>1
⇒ 2r+1>3(r+1) for r>1
So, if P(r) is true, then P(r+1) is also true.
For, n=1, P(1):
L.H.S=2
R.H.S=3
As L.H.S<R.H.S
So, it is not true for n=1
Hence, P(n) is not true for all natural numbers.