How many 3-digit number can be formed by using the digits 1 to 9 if no digit is repeated?

Given: Digits which can be used to make numbers are 1, 2, 3, 4, 5, 6, 7, 8 and 9


The number of these digits are 9


To find: total number of three-digit numbers with no digit repeated


Formula used:


Number of arrangements of n things taken r at a time = P(n, r)



The total number of ways


= the number of arrangements of 9 things taken 3 at a time


= P(9, 3)





= 9 × 8 × 7


= 504


Hence, total number of three-digit numbers using digits 1 to 9 with no digit repeated are 504


29