How many 3-digit number can be formed by using the digits 1 to 9 if no digit is repeated?
Given: Digits which can be used to make numbers are 1, 2, 3, 4, 5, 6, 7, 8 and 9
The number of these digits are 9
To find: total number of three-digit numbers with no digit repeated
Formula used:
Number of arrangements of n things taken r at a time = P(n, r)
∴ The total number of ways
= the number of arrangements of 9 things taken 3 at a time
= P(9, 3)
= 9 × 8 × 7
= 504
Hence, total number of three-digit numbers using digits 1 to 9 with no digit repeated are 504